[Request] How accurate is this?(i.redd.it)

Not very. Sound is a logarithmic scale and can't be directly added/multiplied. The formula is: dB = 10log (W) +120. So each cat is producing 70 = 10log(W) +120 watts, which is W =10^{[(70-120)/10]} or W = 10^{-5} watts. Now this value CAN be multiplied or added. So 2 bn cats * 10^{-5} W/cat = 210^{4.} Now converting back to dB gives: dB =10log(2e4)+120, which is 43+120 = 163 dB. This is like shooting a loud gun or the finale of a firework show right up close. Remember sound energy doubles every 3 dB, so from 1 to 2bn is doubling ~31 times, so sound should increase about 93 dB. From 70 to 163 is exactly 93 dB, so the math checks and makes sense.